Value error all arguments

How to correct a #VALUE! error in the IF function

IF is one of the most versatile and popular functions in Excel, and is often used multiple times in a single formula, as well as in combination with other functions. Unfortunately, because of the complexity with which IF statements can be built, it is fairly easy to run into the #VALUE! error. You can usually suppress the error by adding error-handling specific functions like ISERROR, ISERR, or IFERROR to your formula.

Problem: The argument refers to error values

When there is a cell reference to an error value, IF displays the #VALUE! error.

Solution: You can use any of the error-handling formulas such as ISERROR, ISERR, or IFERROR along with IF. The following topics explain how to use IF, ISERROR and ISERR, or IFERROR in a formula when your argument refers to error values.

IFERROR was introduced in Excel 2007, and is far more preferable to ISERROR or ISERR, as it doesn’t require a formula to be constructed redundantly. ISERROR and ISERR force a formula to be calculated twice, first to see if it evaluates to an error, then again to return its result. IFERROR only calculates once.

=IFERROR(Formula,0) is much better than =IF(ISERROR(Formula,0,Formula))

Problem: The syntax is incorrect

If a function’s syntax is not constructed correctly, it can return the #VALUE! error.

Solution: Make sure you are constructing the syntax properly. Here’s an example of a well-constructed formula that nests an IF function inside another IF function to calculate deductions based on income level.

=IF(E2 IF(the value in cell A5 is less than 31,500, then multiply the value by 15%. But IF it’s not, check to see if the value is less than 72,500. IF it is, multiply by 25%, otherwise multiply by 28%).

To use IFERROR with an existing formula, you just wrap the completed formula with IFERROR:

=IFERROR(IF(E2 Note: The evaluation values in formulas don’t have commas. If you add them, the IF function will try to use them as arguments and Excel will yell at you. On the other hand, the percentage multipliers have the % symbol. This tells Excel you want those values to be seen as percentages. Otherwise, you would need to enter them as their actual percentage values, like “E2*0.25”.

Need more help?

You can always ask an expert in the Excel Tech Community or get support in the Answers community.

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How to correct a #VALUE! error in the SUMPRODUCT function

This topic covers the common scenarios of the #VALUE! error when working with SUMPRODUCT.

Problem: The array arguments don’t have the same dimension

All of the array arguments should be the same dimension. If they’re not, then you get the #VALUE! error. For example, if Array 1 refers to a range of 3 rows and 2 columns, then Array 2 must also correspond to the similar range.

Will fail since the referenced ranges aren’t the same number of rows (13 in the first range, but only 10 in the second).

Solution: Change the formula to:

So that both ranges have the same starting and ending row numbers, and retry the formula.

Problem: One or more cells in the range contain text

If one or more cells in the referenced range contains text or is formatted as a Text data type, you will get the #VALUE! error. The text could be the result of a calculation from another formula, or maybe the cell is simply not formatted correctly.

Solution: Check for any cell that contains text, or is formatted as text and set to the correct data type.

Need more help?

You can always ask an expert in the Excel Tech Community or get support in the Answers community.


Python ValueError Exception Handling Examples

While we believe that this content benefits our community, we have not yet thoroughly reviewed it. If you have any suggestions for improvements, please let us know by clicking the “report an issue“ button at the bottom of the tutorial.

1. What is Python ValueError?

Python ValueError is raised when a function receives an argument of the correct type but an inappropriate value. Also, the situation should not be described by a more precise exception such as IndexError.

2. ValueError Example

You will get ValueError with mathematical operations, such as square root of a negative number.

3. Handling ValueError Exception

Here is a simple example to handle ValueError exception using try-except block.

Here is the output of the program with different types of input.

Our program can raise ValueError in int() and math.sqrt() functions. So, we can create a nested try-except block to handle both of them. Here is the updated snippet to take care of all the ValueError scenarios.

4. Raising ValueError in a function

Here is a simple example where we are raising ValueError for input argument of correct type but inappropriate value.

5. References

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Python typeerror: not all arguments converted during string formatting

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In Python, typeerror: not all arguments converted during string formatting occurs mainly in 3 different cases.

  1. Applying incorrect format Specifier
  2. Incorrect formatting and substitution of values during string interpolation
  3. Mixing different types of format specifiers

Resolving typeerror: not all arguments converted during string formatting

In Python, TypeError occurs if you perform an operation or use a function on an object of a different type. Let us look at each of the scenarios in depth with examples and solutions to these issues.

Applying incorrect format Specifier

If you use the percentage symbol ( % ) on a string, it is used for formatting, and if you are using it on an integer, it is for calculating the modulo.

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If you look at the below code to check odd or even numbers, we accept an input number in the form of string and perform modulus operation ( % ) on string variable. Since it cannot perform a division of string and get the reminder, Python will throw not all arguments converted during string formatting error.

Solution – The best way to resolve this issue is to convert the number into an integer or floating-point if we perform a modulus operation.

Incorrect formatting and substitution of values during string interpolation

In this example, we are performing a string interpolation by substituting the values to the string specifiers. If you notice clearly, we are passing an extra value country without providing the specifier for which Python will throw a not all arguments converted during string formatting error.

Solution – You could resolve the issue by matching the number of specifiers and values, as shown above.

Mixing different types of format specifiers

The major issue in the below code is mixing up two different types of string formatting. We have used <> and % operators to perform string interpolation, so Python will throw TypeError in this case.

Solution – The % operator will be soon deprecated, instead use the modern approach <> with .format() method as shown below.

The .format() method replaces the values of <> with the values specifed in .format() in the same order mentioned.


Solve the TypeError: Not All Arguments Converted During String Formatting in Python

String formatting in Python can be done in various ways, and a modulo ( % ) operator is one such method. It is one of the oldest methods of string formatting in Python, and using it in the wrong way might cause the TypeError: not all arguments converted during string formatting to occur.

Not just that, many other reasons can cause the same. Let us learn more about this error and the possible solutions to fix it.

TypeError is a Python exception raised when we try to operate on unsupported object types. There are many scenarios where we can get this error, but in this article, we will look at the Python TypeError that occurs from the incorrect formatting of strings.

Without further ado, let us begin!

Causes and Solutions for TypeError: Not All Arguments Converted During String Formatting in Python

There are many reasons why the TypeError: not all arguments converted during string formatting might occur in Python. Let us discuss them one by one, along with the possible solutions.

Operations on the Wrong Data Type in Python

Look at the example given below. Here, we take the user’s age as input and then use the modulo operator ( % ).

The result is stored in the variable ans , which is then formatted to the string in the print statement. But when we run this code, we get the TypeError .

This happens because Python takes input in the form of a string. This means that the value 19 taken as the input is considered the str data type by Python.

But can we use a modulo operator ( % ) on a string? No, and hence, we get this error.

To fix this, we must take the input as an integer using the int() function. This is done below.

You can see that this time we get the desired output since the int() function converts the input to integer data type, and we can use the modulo operator ( % ) on it.

Absence of Format Specifier With the String Interpolation Operator in Python

This case is a little bit similar to the one we discussed above. Look at the example given below.

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The output shows us that the error occurred in line 2. But can you guess why?

The answer is simple. We know that anything inside single or double quotes in Python is a string.

Here, the value 19 is enclosed in double quotes, which means that it is a string data type, and we cannot use the modulo operator ( % ) on it.

To rectify this, we will use the int() format specifier, as done below.

This time the code runs fine.

Unequal Number of Format Specifiers and Values in Python

We know that we put as many format specifiers during string formatting as the number of values to be formatted. But what if there are more or fewer values than the number of format specifiers specified inside the string?

Look at this code. Here, we have three variables and want to insert only two of them into the string.

But when we pass the arguments in the print statement, we pass all three of them, which no doubt results in the TypeError .

Let us remove the last variable, actress , from the list of arguments and then re-run this program.

You can see that this time the code runs fine because the number of format specifiers inside the string is equal to the number of variables passed as arguments.

Note that the format specifier to be used depends on the data type of the values, which in this case is %s as we are dealing with the string data type.

Use of Different Format Specifiers in the Same String in Python

We know that there are several ways in which we can format a string in Python, but once you choose a method, you have to follow only that method in a single string. In other words, you cannot mix different types of string formatting methods in a single statement because it will lead to the TypeError: not all arguments converted during string formatting .

Look at the code below to understand this concept better.

We are using placeholders(<>) inside the string to format this string, but we do not pass the arguments as a tuple as we did earlier. Instead, one of the variables is preceded with a modulo operator ( % ) while the other one is not.

This is what leads to the TypeError .

To fix this, we can do two things.

If you want to use placeholders(<>) inside the string, then you must use the format() method with the dot ( . ) operator to pass the arguments. This is done below.

​You can see that this time the code runs fine.

The other way could be to drop the use of placeholders(<>) and use format specifiers in their place along with passing the arguments as a tuple preceded by the modulo operator ( % ). This is done as follows.

Note that the modulo operator ( % ) for formatting is an old-style while, on the other hand, the use of the placeholders with the .format() method is a new-style method of string formatting in Python.

This is it for this article. To learn more about string formatting in Python, refer to this documentation.


In this article, we talked about the various reasons that lead to TypeError: Not all arguments converted during string formatting in Python, along with the possible fixes.